WebIf the work function of a metal is 6.63 × 10-19 J, the maximum wavelength of the photon required to remove a photoelectron from the metal is nm. (Nearest integer) [Given: h=6.63 × 10-34 J s, and c =3 × 108 m s -1 ] Q. Web26 dec. 2024 · Answer: (E) = 1.54ev Explanation: Maximum kinetic energy of emitted photoelectrons = hf - Ф where h is Planck's constant = 6.63*10⁻³⁴ ,f is frequency = c/λ, c = velocity of light = 3.0*10⁸m/s, λ is wavelength of light = 310nm 310*10⁻⁹m, Ф = work function of metal = 2.46eV max K.E. = hc/λ - Ф
How to calculate the work function of a metal? Physics Forums
Web(a) If the work function for a certain metal is 1.5eV,what is the stopping potential for electrons ejected from the metal when the light of wavelength 500nM shines on the metal? (b) What is the maximum speed of the ejected electrons from … Web14 jul. 2013 · Calculate the work function of the metal. I did this: E=Ek+W W=E+Ek W=hc/Lambda -Ek = (6.63E-34J.s) (3.00E8m/s)/3.50E2m)-1.20eV =-1.2 That answer is wrong the correct one is 2.35 eV. what did i do wrong, PLS help me ty and show me what I should of done so i Dont repeat this mistake again. Answers and Replies Jul 14, 2013 #2 … chase up karachi shirts
The work function of a metal is 3.0 eV. It is illuminated by a light …
WebA metal of work function 4eV is exposed to a radiation of wavelength 140 × 10-9min,Then the stopping potential developed by it (h = 6.63 × 10-34Js and c= 3× 108m/s) Q. A metal of work function 4eV is exposed to a radiation of wavelength 140 × 1 0 − 9 m in,Then the stopping potential developed by it ( h = 6.63 × 1 0 − 34 J s and c = 3 × 1 0 8 m / s ) Web31 aug. 2024 · The work function can be written as the following formula: Φ = − eφ − E F where e is the charge of an electron, φ is the electrostatic potential in the vacuum nearby … Web14 nov. 2024 · If the work function of a metal is 6.63×10−19 J, the maximum wavelength of the photon required to remove a photoelectron from the metal is nm. (Nearest integer) … custard\\u0027s only request was for a