WebFind the sum of the first 40 positive integers divisible by 6 . So, the sum of the 40 terms of this AP is 4920. Hence, the sum of the first 40 positive integers divisible by 6 is = 4920. WebFind the Sum of First Forty Positive Integers Divisible by 6. The positive integers divisible by 6 are 6, 12, 18,.. This is an AP with a = 6 and d = 6. Hence, the required sum is 4920. Concept: Sum of First n Terms of

Find the sum of the first 40 positive integers divisible by 6

WebFind the sum of the first 40 positive integers divisible by 6 Easy Solution Verified by Toppr Correct option is A) 6+12+18+24+40 term Here a=6,d=a 2−a 1=12−6=6 n=40,S 40=? S n= 2n[2a+(n−1)d] S 40= 240[2×6+(40−1)6] =20[12+39×6] =20[12+234] =20×246 ∴S 40=4920. Video Explanation Solve any question of Arithmetic Progression with:- Patterns of problems buckle bunnies abortion fund

Sum of first 40 integers divisible by 6 Math Study

Web24 Oct 2008 · Let r, s be two fixed integers greater than 1. A positive integer will be called r-free if it is not divisible by the r th power of any prime.. In a series of papers ((l)–(5)) Evelyn and Linfoot considered the problem of determining an asymptotic formula for the number Q r, s (n) of representations of a large positive integer n as the sum of s r-free integers; for s … WebFirst term =a=7Difference between terms =d=7Number of terms =n=40Sum =S= 2n(2a+(n−1)d))S= 240(2×7+(40−1)7))S=20×(2×7+(39)7))S=20×(14+273)S=20×287S=5740. Web15 Apr 2024 · Find the sum of first 40 positive integers divisible by 6. Problems Solved 24.1K subscribers Subscribe 19K views 1 year ago Class 10 ll Arithmetic Progression Ex :- … buckle buccaneer outfit